这个页面已经不再维护更新了，你可以从这里了解最新的进展
一个练手的小脚本，暂时只是实现了签到，还没有很完备的错误处理，而且在实现“全自动签到”上还没有想出什么合理的方案，先把代码贴上现丑了……
使用方法很简单
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python xiami_auto_checkin.py email password |
即把用户名（email）和密码作为参数传进去即可
如果你只是签固定的一个帐号，也可以直接将代码中的读参数改成赋值
这个代码只是最初的版本，你可以在这里看到最新的进展
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#!/usr/bin/python
# encoding:utf-8
import re
import sys
import urllib
import urllib2
import cookielib
def check(response):
"""
docstring for check
"""
pattern = re.compile(r'<div class="idh">(已连续签到\d+天)</div>')
result = pattern.search(response)
if result: return result.group(1)
return False
pass
def main():
"""
docstring for main
"""
# Get email and password
if len(sys.argv) != 3:
print '[Error] Please input email & password as sys.argv!'
return
email = sys.argv[1]
password = sys.argv[2]
# Init
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cookielib.CookieJar()))
urllib2.install_opener(opener)
# Login
login_url = 'http://www.xiami.com/web/login'
login_data = urllib.urlencode({'email':email, 'password':password, 'LoginButton':'登陆',})
login_headers = {'Referer':'http://www.xiami.com/web/login', 'User-Agent':'Opera/9.60',}
login_request = urllib2.Request(login_url, login_data, login_headers)
login_response = urllib2.urlopen(login_request).read()
# Checkin
checkin_pattern = re.compile(r'<a class="check_in" href="(.*?)">')
checkin_result = checkin_pattern.search(login_response)
if not checkin_result:
# Checkin Already | Login Failed
result = check(login_response)
if result :
print '[Succeed] Checkin Already!', email, result
else:
print '[Error] Login Failed!'
return
checkin_url = 'http://www.xiami.com' + checkin_result.group(1)
checkin_headers = {'Referer':'http://www.xiami.com/web', 'User-Agent':'Opera/9.60',}
checkin_request = urllib2.Request(checkin_url, None, checkin_headers)
checkin_response = urllib2.urlopen(checkin_request).read()
# Result
result = check(checkin_response)
if result:
print '[Succeed] Checkin Succeed!', email, result
else:
print '[Error] Checkin Failed!'
pass
if __name__=='__main__':
main() |
有任何问题，欢迎批评指正，更多更新信息，请参见这里